Home Work

A company has a 190.240.0.0/16 block. They now want to re-organise it into large blocks. They wish to have subnets that can handle at least 1000 hosts each.

You can substitute into the formulae 2^S >= subnets required and 2^H-2 >= hosts required – to determine the number of bits required.

Please calculate:

• S = bits used for subnetting
• H= bits used for the number of hosts in each subnet

Also, please calculate the following for the second subnet:

• subnet mask
• subnet address
• first usable address in that subnet
• last usable address in that subnet
• broadcast address of that subnet

Answer:

190.240.0.0./16

It is a class B network: 10111110.11110000.000000/00.00000000

                                                     Network ID                                Host ID

• S = bits used for sub netting =6
• H= bits used for the number of hosts in each sub net =10
• Sub nets=2*6=64
• Hosts=(2*H)-2=1022

Second Subnet:

• sub net mask 255.255.252.0(11111111.11111111.11111100.00000000)
• sub net address :190.240.4.0/22 (10111110.11110000.00000100.00000000)
• first usable address in that subnet:190.240.4.1 (10111110.11110000.00000100.00000001)
• last usable address in that subnet:190.240.7.254
• broadcast address of that subnet:190.240.7.255 (10111110.11110000.00000111.11111111)

Done by : Asha, Vishnupriya, Mariya, Suhaib